1. b² + 6b + 9 = 2. x² + 8x + 16 = 3. y² + y - 20 =
Matematika
natalya1227
Pertanyaan
1. b² + 6b + 9 =
2. x² + 8x + 16 =
3. y² + y - 20 =
2. x² + 8x + 16 =
3. y² + y - 20 =
1 Jawaban
-
1. Jawaban AlifAlsyazani
Penyelesaian :
Pemfaktoran bil.aljabar
__________________________________
1] b² + 6b + 9
= b² + 3b + 3b + 9
= b[b + 3] + 3[b + 3]
= [b + 3][b + 3].
2] x² + 8x + 16
= x² + 4x + 4x + 16
= x[x + 4] + 4[x + 4]
= [x + 4][x + 4].
3] y² + y - 20
= y² + 5y - 4y - 20
= y[y + 5] - 4[y + 5]
= [y - 4][y + 5].
Salam Alaikum.