Matematika

Pertanyaan

Integral 5x²+6x-3/√x




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1 Jawaban

  • InTegRaL

    ∫(5x² + 6x - 3)/√x dx
    = ∫5x²/x^1/2 dx + ∫6x/x^1/2 dx - ∫3x^-1/2 dz
    = 5 ∫x^3/2 dx + 6 ∫x^1/2 dx - 3 ∫x^-1/2 dx
    = 2x^5/2 + 4x^3/2 - 6x^1/2 + C
    = 2x² √x + 4x√x - 6√x + C

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