Matematika

Pertanyaan

1) 2√x-1 < 1
2) (x^2)^x = x^4x-x^2
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1 Jawaban

  • 1.
    2√x-1 < 1
    (√x-1 < 1/2)²
    x-1 < 1/4
    x < 1 + 1/4
    x < 5/4

    x _> 0

    Hp ={ 0<_ x < 5/4}

    2.
    (x^2)^x = x^4x-x^2
    x^2x = x^4x-x²
    2x = 4x - x²
    x² - 2x = 0
    x(x-2) = 0
    x = 0 V x = 2

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