Matematika

Pertanyaan

x²-7x-12 faktor bentuk aljabar

1 Jawaban

  • x² - 7x - 12 = 0
    x1.2 = (-b ± √(b² - 4ac))/2a
    x1.2 = (-(-7) ± √((-7)² - 4(1)(-12))/(2.1)
    x1.2 = (7 ± √(49 + 48))/2
    x1 = (7 + √97)/2
    x2 = (7 - √97)/2

    x² - 7x - 12
    = (x - (7 + √97)/2)(x - (7 - √97)/2)
    = (1/4)(2x - 7 - √97)(2x - 7 + √97)

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