suatu fungsi g(x)=p x + q.jika g (-4)=9 dan g (-1) =3,maka tentukan : a.nilai p dan q b.bentuk fungsi g

g(x)=p x + q
g(-1)=3
-p+q =3

[tex]p= \frac{9-3}{-4-(-1)} = \frac{6}{-3}=-2 [/tex]
-p+q=3
-(-2)+q=3
2+q=3
q=3-2
q=1

g(x) = -2x+1

-4p+q = 9
-p+q = 3
------------------ -
-3p = 6
p = 6/-3
p = -2


-4p+q = 9
-4.-2+q = 9
8+q = 9
q = 9-8
q = 1


jadi, p = -2 dan q = 1