Hitunglah luas yang diarsir

[tex]L= \int\limits^{-2}_2 {(x^2-4)} \, dx +2 .\int\limits^3_2 {(x^2-4)} \, dx \\ \\ = \frac{x^3}{3}-4x \left[\begin{array}{ccc}-2\\2\end{array}\right] +\frac{x^3}{3}-4x \left[\begin{array}{ccc}3\\2\end{array}\right] \\ \\ = \frac{32}{3}+2. \frac{7}{3} \\ \\ =\frac{32}{3}+ \frac{14}{3} \\ \\ =\frac{46}{3}[/tex]