9/√6-√3 sederhanakan bentuk akar

DIRGAHAYU RI KE-72 !!!

9/√6-√3 (√6+√3/ √6+√3)
= 9√6 + 9√3 /6-3
= 3(3√6 +3√3)/ 3
= 3√6 + 3√3

Materi Bentuk Akar

[tex] \frac{9}{ \sqrt{6}- \sqrt{3} } = \frac{9}{ \sqrt{6}- \sqrt{3} }* \frac{ \sqrt{6}+ \sqrt{3} }{ \sqrt{6}+ \sqrt{3} }= \frac{9( \sqrt{6}+ \sqrt{3}) }{6-3} = 3 \sqrt{6}+3 \sqrt{3} [/tex]