persamaan pnyelesaian bentuk fungsi kuadrat(dengan jalannya): a. X²- 7x +12= 0 b. X² + x - 12 =0

Materi : Persamaan Kuadrat

Pembahasan :
x² - 7x + 12 = 0
(x - 4)(x - 3) = 0
x = 3
x = 4

Hp : {3 , 4}

————————————————
x² + x - 12 = 0
(x + 4)(x - 3) = 0
x = -4
x = 3

Hp : {-4 , 3}

————————————————
x² + 2x - 15 = 0
(x + 5)(x - 3) = 0
x = -5
x = 3

Hp : {-5 , 3}

————————————————
x² + x - 20 = 0
(x + 5)(x - 4) = 0
x = -5
x = 4

Hp : {-5 , 4}

————————————————
x² - 3x - 18 = 0
(x - 6)(x + 3) = 0
x = -3
x = 6

Hp : {-3 , 6}

Hai dela sayang...

Aku bantu ya

a. X²- 7x +12= 0

<=> ( x-4)(x-3)

*x-4=0
x = 4

**x-3=0
x = 3

b. X² + x - 12 =0

<=> (x+4)(x-3)

*x+4=0
x = -4

**x-3=0
x = 3



c.X² +2x-15 = 0.

<=> (x+5)(x-3)

*x+5=0
x = -5

**x-3=0
x = 3



d. X²+x-20=0

<=> (x+5)(x-4)

*x+5=0
x = -5

**x-4=0
x = 4


e. X²-3x -18=0

<=> (x+3)(x-6)

*x+3=0
x = -3

**x-6=0
x = 6


Semoga membantu