Matematika

Pertanyaan

gunakan rumus perkalian
a. 4sin45°cos15°
b. sin75°cos15°

1 Jawaban

  • Product Formulas.

    Answer for problem a.
    sin α cos β = 1/2 [sin (α + β) + sin (α - β)]
    4 sin 45° cos 15° = 2 [sin (45° + 15°) + sin (45° - 15°)]
    = 2 (1/2 √3 + 1/2)
    = 1 + √3

    Answer for problem b.
    sin 75° cos 15° = 1/2 [sin (75° + 15°) + sin (75° - 15°)]
    = 1/2 (1 + 1/2 √3)
    = 1/4 (2 + √3)

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