limit fungsi x : (x-3)² (x⇒3)

x / (x-3)^2 =x / ( x^2 -6x + 9) = 3/ (3)^2 - 6(3) + 9 ) = 3/0 = tdk terhingga

[tex] \lim_{x \to 3} \frac{x}{(x-3)^{2}} [/tex]

[tex]= \lim_{x \to 3} \frac{x}{x^{2} - 6x + 9} [/tex]

[tex]= \frac{3}{3^{2} - 6(3) + 9} [/tex]

[tex]= \frac{3}{9 - 18 + 9} [/tex]

[tex]= \frac{3}{0} [/tex]

[tex]= \infty[/tex]