integral (1- cos x) sin x dx batas atas π/2 batas bawah 0

∫(1 - cos x) sin x dx [π/2 ... 0]
= - ∫(1 - cos x) dcos x
= - ∫dcos x + ∫cos x dcos x
= -cos x + 1/2 cos² x [π/2 ... 0]
= (-cos π/2 + 1/2 cos² π/2) - (-cos 0 + 1/2 cos² 0)
= 0 - (-1 + 1/2)
= -(-1/2)
= 1/2