Suatu larutan terbuat dari 36% w/w glukosa yang dilarutkan dalam air. Jika tekanan uap air murni pada suhu 25°c adalah 20mmHg , Kb air 0.52 °c/molal , dan Kf

Massa glukosa = 36 gr (Mr glukosa = 180)
Massa air = 100%-36%=64% = 64 gr (Mr air = 18)
P° = 20 mmHg
Kb = 0,52
Kf = 1,86

nglukosa = 36/180 = 0,2
nair = 64/18 = 3,55
ΔP=P°.xterlarut
ΔP=20. nglukosa/nglukosa + nair
ΔP=20. 0,2/0,2+3,55
ΔP=20. 0,2/3,755
ΔP=20.0,053
ΔP=1,06 mmHg

ΔTb=M.Kb
ΔTb=36/180 x 1000/64 x 0,52
ΔTb=0,2 x 15,625 x 0,52
ΔTb=1,625°C

ΔTf=M.Kf
Δf=3,125 x 1,86
ΔTf=5,8125°C

nt = wt/Mr = 36/180 = 0,2
np = wp/Mr = 64/18 = 3,55
ΔP=P°.Xt
ΔP=20. nt/(nt+np)
ΔP=20. 0,2/(0,2+3,55)
ΔP=20. 0,2/3,76
ΔP=20.0,053
ΔP=1,06 mmHg

ΔTb=M.Kb
ΔTb=36/180 x 1000/64 x 0,52
ΔTb=0,2 x 15,625 x 0,52
ΔTb=1,63°C

ΔTf=M.Kf
Δf=3,125 x 1,86
ΔTf=5,81°C