Tentukan nilai A. 2^x= 1/32 B. 2^3x+1= 128
Matematika
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Tentukan nilai
A. 2^x= 1/32
B. 2^3x+1= 128
A. 2^x= 1/32
B. 2^3x+1= 128
1 Jawaban
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1. Jawaban DeusVult
A.
2^x = 1/2^5
2^x = 2^-5
x = -5
B.
2^(3x+1) = 128
2^(3x+1) = 2^7
<=> 3x + 1 = 7
<=> 3x = 6
<=> x = 2
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