x^2-6x+7=0 berapak pemfaktoran nya dan rumus ABC nya

Materi : Pemfaktoran
Kelas : X SMA

x1,2 = -(-6) +/- √(-6)² - 4(1)(7) / 2(1)
= 6 +/- √36-28 / 2
= 6 +/- √8 /2 = 3+/- √2
x1 = 3 + √2
x2 = 3-√2

Rumus abc
x1.2 = (-b ± √(b² - 4ac)/2a

x² - 6x + 7 = 0
a = 1
b = -6
c = 7

x1.2 = (-(-6) ± √((-6)² - 4(1)(7))/(2.1)
x1.2 = (6 ± √8)/2
x1.2 = (6 ± 2√2)/2
x1.2 = 3 ± √2

akar2 dr x² - 6x + 7 = 0 :
x1 = 3 + √2
x2 = 3 - √2

x² - 6x + 7 = (x - (3 + √2))(x - (3 - √2))