Matematika

Pertanyaan

1. dengan pemfaktoran, tentukan akar-akar persamaan kuadrat berikut.

a. X2-X-2= 0
b. X2-X-12= 0
c. 2X2-X-3= 0
d. 6X2-X-2= 0

1 Jawaban

  • Materi : Persamaan Kuadrat

    Pembahasan :
    x² - x - 2 = 0
    x² + x - 2x - 2 = 0
    x(x + 1) - 2(x + 1) = 0
    (x - 2)(x + 1) = 0
    x = -1
    x = 2

    Hp : {-1 , 2}

    ————————————————
    x² - x - 12 = 0
    x² - 4x + 3x - 12 = 0
    x(x - 4) + 3(x - 4) = 0
    (x + 3)(x - 4) = 0
    x = -3
    x = 4

    Hp : {-3 , 4}

    ————————————————
    2x² - x - 3 = 0
    2x² + 2x - 3x - 3 = 0
    2x(x + 1) - 3(x + 1) = 0
    (2x - 3)(x + 1) = 0
    x = -1
    x = 3/2

    Hp : {-1 , 3/2}

    ————————————————
    6x² - x - 2 = 0
    6x² - 3x + 4x - 2 = 0
    3x(2x - 1) + 2(2x - 1) = 0
    (3x + 2)(2x - 1) = 0
    x = -2/3
    x = 1/2

    Hp : {-2/3 , 1/2}

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