Matematika

Pertanyaan

1/2log (1per16)pangkat-1-3log 1per243 + 5log 1......pake cara

1 Jawaban

  • (1/2)'log (1/16)^-1 - 3'log (1/243) + 5'log 1
    = (2^-1)'log 2^4 - 3'log 3^-5 + 0
    = (4/-1) - (-5)
    = -4 + 5
    = 1

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