Matematika

Pertanyaan

Berapa sih jumlahnya?
Beserta caranya?
Berapa sih jumlahnya? Beserta caranya?

1 Jawaban

  • 1.
    [(24a^3×b^8)/(6a^5×b)]×[(4b^3×a)/(2a)]^2
    = (4a^(-2)b^7) × [(16b^6×a^2)/(4a^2)]
    = (4a^(-2)b^7) × (4b^6)
    = 16a^(-2)b^13
    = (16b^13)/(a^2)


    2.
    (2/3 × ^2 log 64) - (1/2 × ^2 log 16)
    = (2/3 × ^2 log 2^6) - (1/2 × ^2 log 2^4)
    = (2/3 × 6 × ^2 log 2) - (1/2 × 4 × ^2 log 2)
    = (2/3 × 6 × 1) - (1/2 × 4 × 1)
    = 12/3 - 4/2
    = 4 - 2
    = 2