Matematika

Pertanyaan

bentuk sederhana dari √18+2√72¬√32¬√50

1 Jawaban

  • V18 + 2V72 - V32 - V50
    = V(9×2) + 2V(36×2) - V(16×2) - V(25×2)
    = V9V2 + 2V36V2 - V16V2 - V25V2
    = 3V2 + 2×6V2 - 4V2 - 5V2
    = 3V2 + 12V2 - 4V2 - 5V2
    = (3 + 12 - 4 - 5)V2
    = 6V2

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