jika diketahui Kf air 1,86°c/m, larutan NaOH 4% (Mr=40) membeku pada suhu?

∆Tf = 4/40 . 1000/96 . 1,86
∆Tf = 1,937

Tf.lar. = ∆Tf + Tf. murni
= 1,937 + 0
= 1. 937 °C

∆Tf = m.Kf
= 4/40 x 1000/96 x 1,86
= 0,1 x 10,42 x 1,86
= 1,94°C

Tf = 0-1,94 = -1,94°C